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 Replies: 89 / Views: 11,377 |
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Pillar of the Community
 United States
2480 Posts |
 Wheeeeeeee! Great job Argentum! My bid is per atom. One quadrillionth of a cent per atom in the V nickel. As I thought about the sky high sales price of some coins, I thought "sheesh, they must be paying by the atom". So that started me wondering... how many atoms are in a nickel? Dust off the brain, reach way back to basic chemistry... A nickel is 5 grams, 75% Cu, 25% Ni. 3.75 g Cu, 1.25 g Ni. Divide the weight of each element by its atomic weight (in g/mole), add those two numbers, then multiply by Avogadro's constant. The result is ~4.836350x10^22 atoms in the nickel. I moved the decimal until the number was in range for a reasonable guess of the auction price, a7 digit figure-- in this case $4,836,350-- or put another way, one quadrillionth of a cent per atom. I could be wrong on the '-illionth' nomenclature but you get the idea. Argentum, did you get my last hint about the clues found on pages 2 and 3 which were not of my doing? They were YOUR AVATAR, showing the elemental table entry for silver with its atomic weight in g/mole.  I'll take your prize package to the post office on Monday. Hope everyone enjoyed this little riddle! Thanks for the entertainment, my CCF family  Edited by ThisIsFun
02/03/2013 04:52 am
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Pillar of the Community
United States
1195 Posts |
Quote:
Argentum, did you get my last hint about the clues found on pages 2 and 3 which were not of my doing? They were YOUR AVATAR, showing the elemental table entry for silver with its atomic weight in g/mole. So THATS what you meant! I was  trying to figure it out from the content of the posts, then figured pull something outo of left field on "approximately" and "think small". I'll get you my address, then to bed with me! WOW what a hard contest, and a good one. I might run a similar one.  Edited by argentum
02/03/2013 04:26 am
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Pillar of the Community
United States
3453 Posts |
Congratulations! I was working the chemistry angle but hadn't quite gotten there. Way to go on this one!
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Pillar of the Community
Canada
3167 Posts |
Congrats! Thanks for the game!
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Valued Member
Canada
189 Posts |
WOW, great contest and congrats to argentum to solving the riddle.
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Pillar of the Community
United States
1088 Posts |
Congrats to the victor! There is a large write up on this particular coin in my local paper today. Cool story.
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Pillar of the Community
United States
814 Posts |
Congrats argentum. Quite the mind you have there. And to you TIF. One heck of a contest.
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Valued Member
United States
360 Posts |
Good job argentum, I'm just glad this contest is over!
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Pillar of the Community
United States
4897 Posts |
Very nice Thisisfun! Congrats Argentum!
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Pillar of the Community
United States
2189 Posts |
Congrats argentum! Thanks for saving us....I never would have got that one. @This is Fun....That was Fun!  |
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Bedrock of the Community
United States
10038 Posts |
I was geeking the other way by playing with the IP address of CCF, the thread ID post, and TIF's CCF ID. I used ASCII and various other manipulations with the number 5 (for 5 known) and the number 1913.
I keep forgetting the word geek is applied to many areas nowadays.
Thanks for the great contest and congrats to Argentum!
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Pillar of the Community
United States
1195 Posts |
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Pillar of the Community
United States
2480 Posts |
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Pillar of the Community
United States
2480 Posts |
While re-reading this thread tonight, I found a careless mistake in my explanation.  I meant that my "bid" was 4.83635 quadrillionths of a cent per atom, not 1 quadrillionth of a cent per atom. Edited by ThisIsFun
03/26/2014 10:16 pm
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Replies: 89 / Views: 11,377 |
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Posted 02/03/2013 04:23 am
