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 Replies: 203 / Views: 19,227 |
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Valued Member
Australia
95 Posts |
Is the 2nd 3rd words (together) LF E MB A MPPA TEA EIOE FQ I XZ AA?
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Bedrock of the Community
Canada
11922 Posts |
I have been playing with one idea since near the beginning of the game, but I am still not exactly sure how it would work. Anyways...
We know a single U is an E, so how many other groups of one are there in total?
If the answer to the above question is one other group, is it the letter D?
If yes to the above question, does the letter D decode into a T?
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Pillar of the Community
United States
853 Posts |
I've tried math in every basic way I can think of. I don't know why I tried the charts, because without a keyword, you are randomly guessing with more than a billion possible combos, and I haven't seen a chart to figue a 4 letter encoded character. I think we are all overlooking some simple solution...but then again, maybe not.
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Pillar of the Community
 United States
8904 Posts |
Quote:
is the grouping of uncoded letters that equals one coded letter use anything as separation markers or is it just random and the letters you used in the code only serve the purpose of figuring out the coded letter and you have to guess at the separation? I think you mean, is the group of CODED letters (in the coded message) that equals one UNCODED letter? At least that's the way I'm going to answer it!  There are no separation markers. I've used spaces in the hints to differentiate between the letters used to code the letters in the original message. But, as we've seen, not all the needed spaces are yet apparent. Nothing is random.  Like I said, you do still have to figure out the separations between some of the words. Edited by Moe145
01/17/2016 6:23 pm
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Bedrock of the Community
Canada
11922 Posts |
Opps, I forgot B and J were alone. I am thinking too much; please ignore my second question in my last post.
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Pillar of the Community
United States
8904 Posts |
Is the 2nd 3rd words (together) LF E MB A MPPA TEA EIOE FQ I XZ AA?
Yes, but that grouping you show is not correct.
Hint#15: The second word's correct grouping is:
LF
EM
BAMP
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Pillar of the Community
United States
8904 Posts |
Quote:
We know a single U is an E, so how many other groups of one are there in total?
If the answer to the above question is one other group, is it the letter D?
If yes to the above question, does the letter D decode into a T? Boy, you all are making me work hard!! A single U does indeed equal an E. Hint # 16: There are only two letters represented by a single coded letter. The other letter represented by a single letter is NOT D. A single lone D in the code would decode into a T. |
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Pillar of the Community
United States
853 Posts |
... But Joseph, there isn't a D in the code.
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Pillar of the Community
United States
853 Posts |
Hint 16 should point you to letter J. We already know that J is the single last code group for word 5.
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Moderator
 United States
34410 Posts |
Here is my thinking. I recognize that it doesn't work completely, but maybe someone can pick up this torch and carry it over the goal line (or else ignore this as a red herring). It is very easy to assign each letter the alphabet by sequential number (a=1, b=2, c=3, ..., z=26). In *some* cases, there is math that works out to the hints that we have been given. For example, the code QD would correspond to 17 and 4. Well, obviously 17-4=13 and the letter M is the 13th letter. Similarly, with the code U, you could solve [26]-21= 5 and know that E is the 5th letter. But then it breaks down.  In the hypothetical case of the code D (which we know doesn't actually exist in this message), the formula would be [26]-4 = 22 and the twenty second letter is V, but we are told that it actually would be T. Similarly, TZ seems to yield either F or T (the sixth to last letter because you have a minus six) not the M that we have been told. Any thoughts folks? "If you climb a good tree, you get a push."
-----Ghanaian proverb
"The danger we all now face is distinguishing between what is authentic and what is performed."
-----King Adz
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Pillar of the Community
United States
8904 Posts |
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Pillar of the Community
United States
1249 Posts |
So wait doesn't B = single letter and also J= single letter and U = e?
That's three right?
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Pillar of the Community
United States
853 Posts |
I tried that...and also adding them... And also a Cesar shift on all 26 letters and then adding & subtracting them. Ending in 7 total pages of scribble. Unless I messed up somewhere, and that's possible, that's not the solution. All I came up with for the first word, that was actually a word, is SOUP.
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Bedrock of the Community
Canada
11922 Posts |
Quote:
... But Joseph, there isn't a D in the code. I know  That was was just obvious to me, and D equalling T in a way confirms what I was thinking. I've got them hamsters runnin' in my head now  |
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Pillar of the Community
United States
1249 Posts |
I'm with jay on that I have tried all of that and multiple ways I don't want to help anybody but it may be the only way it will get solved. There has to be a rule or something for when there are multiple letter . Well their doesn't have to be but I think there is. So rule for example when 2 letters equal on you have to add them together minus 20 and minus 30 for 3 letters in a word ect ect ? but nothing I tried has worked even using different addings and subtractings and different rules and combinations
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Replies: 203 / Views: 19,227 |
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Posted 01/17/2016 6:07 pm
