One can do the maths.
Let's assume for starters that the object is actually still made of regualr coinage bronze. Density = mass / volume. Therefore volume = mass / density. The volume of a piece of bronze weighing 66 grams is therefore 66 / 8.9 = 7.42 cubic centimetres.
The volume a cylinder = pi x radius^2 x height. The height of a cylinder of known volume is therefore = volume / (pi x radius^2).
A Lincoln Cent has a radius of 0.925 cm. This now gives us a height of our postulated cylinder = 7.42 / (3.14159 x 0.925^2) = 2.76 cm, or just over one inch thick. I don't think that would comfortably fit inside a standard slab.
Let's assume for starters that the object is actually still made of regualr coinage bronze. Density = mass / volume. Therefore volume = mass / density. The volume of a piece of bronze weighing 66 grams is therefore 66 / 8.9 = 7.42 cubic centimetres.
The volume a cylinder = pi x radius^2 x height. The height of a cylinder of known volume is therefore = volume / (pi x radius^2).
A Lincoln Cent has a radius of 0.925 cm. This now gives us a height of our postulated cylinder = 7.42 / (3.14159 x 0.925^2) = 2.76 cm, or just over one inch thick. I don't think that would comfortably fit inside a standard slab.
Don't say "infinitely" when you mean "very"; otherwise, you'll have no word left when you want to talk about something really infinite. - C. S. Lewis
























